How the Martingale works at a fixed Spaceman cash-out target
The Martingale is a staking system: you pick a base stake, double it after every loss and go back to the base stake after a win. The idea is that the one win that eventually arrives pays back every earlier loss and leaves a profit of exactly one base unit. In Spaceman it is usually paired with a fixed cash-out target such as 2x, because at 2x a win returns twice the stake, so a doubled stake after a loss recovers the whole run.
This page explains the arithmetic honestly. It is not a recommendation. The system changes how losses are distributed over time, not how large they are on average.
The assumptions behind every number
All figures below use one simple model, so you can check them yourself:
- Cash-out is full and automatic at 2x. Spaceman also allows partial cash-outs, which this page does not model.
- With an RTP of 96.5%, the chance that a round reaches a multiplier m is modelled as 0.965 / m. At 2x that is 48.25% to win and 51.75% to lose.
- Every round is independent. A loss does not make a win more likely next round.
- Results are long-run averages. They say nothing certain about the next session. Operators can differ in details, and the rules screen of the casino you use is the reference for RTP and limits.
Stakes after consecutive losses
Take a base stake of 1 unit (the unit can be any amount). After n losses in a row the next stake is 2^n units, and the money already lost is 2^n - 1 units.
| Losses in a row | Next stake | Already lost | Chance of this run | Roughly 1 in |
|---|---|---|---|---|
| 1 | 2 | 1 | 51.75% | 2 |
| 2 | 4 | 3 | 26.78% | 4 |
| 3 | 8 | 7 | 13.86% | 7 |
| 4 | 16 | 15 | 7.17% | 14 |
| 5 | 32 | 31 | 3.71% | 27 |
| 6 | 64 | 63 | 1.92% | 52 |
| 7 | 128 | 127 | 0.99% | 101 |
| 8 | 256 | 255 | 0.51% | 194 |
| 9 | 512 | 511 | 0.27% | 376 |
| 10 | 1,024 | 1,023 | 0.14% | 726 |
| 12 | 4,096 | 4,095 | 0.04% | 2,711 |
| 15 | 32,768 | 32,767 | 0.005% | 19,559 |
The "chance" column is 0.5175 raised to the number of losses, counted from the start of a cycle (a cycle begins right after a win, or at the very start).
What the table shows
- Every successful cycle earns just 1 unit, no matter how long it took.
- To earn that 1 unit after a 10-loss run you must be able to stake 1,024 units, with 1,023 units already gone. If that stake loses too, the total lost is 2,047 units.
- The stake grows by a factor of 2 per round, while the chance of the run only shrinks by a factor of about 1.93 (1 / 0.5175). The exposure grows faster than the probability falls.
How likely is a long losing run?
A single cycle is one thing. Over many rounds, long runs are no longer rare. The probability of at least one run of k consecutive losses somewhere in N rounds, computed exactly for the 51.75% loss rate, is:
| Rounds played | Run of 7 losses | Run of 10 losses |
|---|---|---|
| 100 | 37.7% | 6.0% |
| 500 | 91.5% | 28.1% |
| 1,000 | 99.3% | 48.5% |
| 2,000 | above 99.9% | 73.6% |
So a run of 10 losses is roughly a coin flip over 1,000 rounds. Its chance at any given start is small, but the Martingale keeps starting new cycles, so the opportunities add up.
Bias warning. Short sessions usually look good. With a 7-bet limit (stakes 1 to 64, 127 units in total) a cycle succeeds with probability 1 - 0.5175^7, about 99.0%, and a success pays only 1 unit. The remaining 1.0% costs 127 units. Many small wins feel like a working system until the rare cycle arrives.
Bankroll limits and table limits
Two hard ceilings stop the doubling before the theory does.
Your own bankroll
A bankroll of 1,023 units funds exactly 10 bets (1, 2, 4 ... 512). If all 10 lose, you are out of money and cannot place the 11th bet. The loss is 1,023 units, which took roughly 1,000 successful cycles of 1 unit to build up. See bankroll management in Spaceman for how sizing a bankroll relates to variance.
The operator's maximum stake
Casinos set a maximum stake per round, and the figure differs by operator and by table or currency. Check the rules or limits shown in the game you use. As an illustration only: if the maximum were 100 units and the base were 1 unit, the system would break after 7 losses (127 units gone), because the required next stake of 128 is not allowed. That happens in about 1 cycle in 101, and at that point you cannot recover by doubling any more.
A larger base stake reaches the cap after fewer doublings.
Why it does not remove the house edge
Every single round has an expected return of 96.5% of the stake, whatever the stake is. That is the 3.5% house edge. A staking system only decides how large each stake is. The expected loss is therefore 3.5% of the total amount staked, no matter how the stakes are arranged.
The Martingale increases the total amount staked, and a larger total means a larger expected loss. For a cycle limited to 7 bets, the average amount staked per cycle is about 7.78 units, so the expected result is 7.78 x (-3.5%) = -0.27 units per cycle, even though 99.0% of cycles end with +1. For a 10-bet limit the figure is about -0.41 units per cycle. A deeper chain means a larger expected loss, not a smaller one.
Another way to see it: 99.0% x (+1) + 1.0% x (-127) is about -0.27. The frequent small gains and the rare large loss cancel out, with a bit more on the loss side.
If you want to see how the 96.5% figure turns into these probabilities, read Spaceman RTP explained and the probability maths of Spaceman.
Common misunderstandings
- "A win is due after several losses." This is the gambler's fallacy. After 6 losses the chance of winning the next round is still 48.25%.
- "I will stop before it gets bad." Stopping early only means taking the loss earlier. Every stopping rule leaves the expected loss at 3.5% of what you stake.
- "A higher target means fewer losses to recover." At higher targets the win chance is lower, so runs of losses are longer and the doubling is steeper than 2x.
- "A [predictor](/spaceman/spaceman-predictor) or bot can tell me when to start." Outcomes come from a certified random number generator. Nothing can forecast them.
For a broader look at what staking plans can and cannot do, see Spaceman strategy: what the numbers say.
Summary
- The Martingale at a 2x target wins 1 base unit in most cycles and loses a very large amount in a few.
- The stake after 10 losses is 1,024 times the base, with 1,023 already lost; a 7-loss run (about 1 cycle in 101) already costs 127 units.
- Over 1,000 rounds, a 10-loss run has roughly a 48.5% chance of occurring at least once.
- Table limits and your own bankroll cap the doubling, so the final recovery bet may not even be allowed.
- The system cannot change the 3.5% house edge. It increases the amount staked and so the expected loss.
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Responsible gambling: This article is educational and is not betting or financial advice. Play only if you are an adult where gambling is legal, and only with money you can afford to lose. If gambling stops being fun or you feel you are chasing losses, stop and seek free help from BeGambleAware or Gamblers Anonymous.